Arginine source and determination method Home News Industry News
Arginine source and determination method

Source
Arginine can be from any food that contains protein intake, such as meat, poultry, cheese, fish and so on. The food is rich in arginine include chocolate, peanuts and walnuts.

Determination

Method name
Arginine - Arginine Determination - potentiometric titration

Applications
The method uses potentiometric titration arginine (C6H14N4O2) content.
 The method is suitable for the determination of arginine.

Principle of the method
Anhydrous formic acid plus test dissolve, add glacial acetic acid, according to potentiometric titration with perchloric acid titration solution (0.1mol / L) titration, and the results of titration experiments with blank correction, which was. Each 1mL perchloric acid titration solution (0.1mol / L) is equivalent to 8.710mg of C6H14N4O2.
Reagents:
1 Water (new place to boiling temperature)
2 acetic acid
3 anhydrous formic acid
4 perchloric acid titration solution (0.1mol / L)
5 basis of potassium hydrogen phthalate
6 anhydrous acetic acid
7 crystal violet indicator solution
 Equipment:
Sample Preparation:
 1 perchloric acid titration solution (0.1mol / L)
Preparation: anhydrous acetic acid (water content calculated by each 1g of water plus acetic anhydride 5.22mL) 750mL, adding perchloric acid (70 ~ 72%) 8.5mL, shake, let cool, add the appropriate amount of anhydrous acetic acid into 1000mL, shake, place 24 hours. If the measured test easy to acetylation, shall be determined with a moisture content of the liquid water content, water and acetic anhydride and then adjust to the liquid water content of 0.01% to 0.2%.
Calibration: Take dried at 105 ℃ to constant weight of potassium hydrogen phthalate reference about 0.16g, accurately weighed, add 20mL of anhydrous acetic acid to dissolve, add 1 drop of crystal violet indicator solution used to titrate the solution slowly blue, and the results of titration experiments with blank correction. Each 1mL perchloric acid titration solution (0.1mol / L) is equivalent to 20.42mg of potassium hydrogen phthalate. According to the consumption of the liquid with potassium hydrogen phthalate to take the amount, calculate the concentration of the solution.

 2 crystal violet indicator solution
Take crystal violet 0.5g, add 100mL glacial acetic acid dissolve.
 Storage: home brown glass bottles, sealed.
Steps: take the product of about 80 mg, accurately weighed, add 3mL of anhydrous formic acid to dissolve, add glacial acetic acid 50mL, according to the potentiometric titration, titration with perchloric acid solution (0.1mol / L) titration, and titration The results with the blank test correction, which was. Each 1mL perchloric acid titration solution (0.1mol / L) is equivalent to 8.710mg of C6H14N4O2.

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